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1840 United States presidential election in North Carolina

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1840 United States presidential election in North Carolina

← 1836 October 30 - December 2, 1840 1844 →
 
Nominee William Henry Harrison Martin Van Buren
Party Whig Democratic
Home state Ohio New York
Running mate John Tyler none
Electoral vote 15 0
Popular vote 46,567 34,168
Percentage 57.68% 42.32%

County Results

President before election

Martin Van Buren
Democratic

Elected President

William Henry Harrison
Whig

The 1840 United States presidential election in North Carolina took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose 15 representatives, or electors to the Electoral College, who voted for President and Vice President.

North Carolina voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won North Carolina by a margin of 15.36%.

With 57.68% of the popular vote, North Carolina would prove to be Harrison's fifth strongest state after Kentucky, Vermont, Rhode Island and Louisiana.[1]

Results

[edit]
United States presidential election in North Carolina, 1840[2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Whig William Henry Harrison of Ohio John Tyler of Virginia 46,567 57.68% 15 100.00%
Democratic Martin Van Buren of New York Richard M. Johnson of Kentucky 34,168 42.32% 0 0.00%
Total 80,735 100.00% 15 100.00%

References

[edit]
  1. ^ "1840 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
  2. ^ "1840 Presidential General Election Results - North Carolina". U.S. Election Atlas. Retrieved December 23, 2013.